Code for Armstrong number

Question

I have wrote the code for armstrong number where each digits are raised to thhe power of total digits in the number

Please help it because I'm not getting the correct code

#include <iostream>
using namespace std;
float power(int base, int exp)
{
float n = 1.0;
for (int i = 0; i < exp; i++)
{
n = n * base;
}
return n;
}
void arm(int a)
{
int count = 0, rem = 0;
int num=0;
while (a > 0)
{
a /= 10;
count++;
}
cout << count << endl;
while (a > 0)
{
rem = a % 10;
num =num+ power(rem, count);
a /= 10;
//cout << num << endl;
}
cout << num;
}
int main()
{
cout << "Enter the number ";
int n;
cin >> n;
arm(n);
return 0;
}

Answer 1

I am telling you what's happening :
in this line,
while (a > 0)
{
a /= 10;
count++;
}
a becomes 0.
So when it goes to this line,
while (a > 0)
{
rem = a % 10;
num =num+ power(rem, count);
a /= 10;
//cout << num << endl;
}
it doesn't go inside this loop.
As a result , num=0 declared in the very beginning of that function ,still remains the same and prints 0.

Answer 2

The future is now thanks to science thanks ☺️ ! Actually I forgot the fact that value of a gets changed In first while loop thanks ! Buddy !