What's wrong with my code?

Question

It keeps saying that it can recognize symbol in the scanner (System.in) area. Please help. I'm trying to make a calculator in Java.

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner num = newScanner(System.in);
int n = num.nextInt();
String op = num.nextLine();
int n2 = num.nextInt();
if (op == "+") {
System.out.println(n + n2);
}
if (op == "-") {
System.out.println(n - n2);
}
if (op == "x") {
System.out.println(n * n2);
}
if (op == "/") {
System.out.println(n / n2);
}
}
}

Answer 1

import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner num = new Scanner(System.in);
int n = num.nextInt();
char op =num.next(). charAt(0);
int n2 = num.nextInt();
if(op=='+') {
System.out.println(n + n2);
}
if(op=='-') {
System.out.println(n - n2);
}
if(op =='*') {
System.out.println(n * n2);
}
if(op == '/') {
System.out.println(n / n2);
}
}
}

//Check out the syntax once again, I have modified a bit.

Answer 2

In case you're wondering what num.next().charAt(0) does, you can have a look at my answer in this thread -

https://www.sololearn.com/discuss/2736943/?ref=app

Answer 3

You're welcome, Ava🙂. Btw, you can also ping someone using the @ symbol like this Ava, so they will get a notification you did so.

Answer 4

Scanner num = new Scanner(System.in)

Answer 5

Use char instead of string in declaring the variable op. If you use string, the n is correctly read as an integer and the remaining part that is op and n2 are togetherly read as a string. Just modify your program and you will achieve correct output.
Good luck👍

Answer 6

Aditiya, thank you. This greatly helped me. It will be great for me to get to study the syntax

Answer 7

Thank you so much for explaining, Soumik

Answer 8

Soumik thanks

Answer 9

Go

Answer 10

Leave a space between new keyword and scanner....
And take op input as a character....
Or else use op.equals() instead of ==

Answer 11

Mm

Answer 12

Use * instead of x