Why inputing 'a' wouldn't make the output 1?

Question

In the following code inputing 'a' wouldn't make name[count] == a as true. Does anyone know why it wouldn't be true?

#include <stdio.h>

int main(void) {
char name[1000][14];
int count = 0;
scanf("%s", &name[count]);
printf("%s\n", name[count]);
printf("%s\n", "a");
printf("%d", name[count] == "a");

return 0;
}

If I input a this is what I get.
a
a
a
0

Answer 1

First, remove & before name[count] in scanf(). name[count] is already an address.

Second, in order to compare 2 strings, you should use strcmp(). == will compare 2 addresses rather than the content. In order to use strcmp(), you need to #include <string.h>.

strcmp() returns 0 if 2 strings are equal. So you can do:
printf("%d", strcmp(name[count], "a") == 0);

Answer 2

You should compare to the character literal 'a' instead of comparing to the string literal "a"

Answer 3

Then you should use the function strcmp() from <string.h> which compares two strings and returns 0 if they are equal

Answer 4

Then how about if I want to compare name[count] and "aa"?

Answer 5

CarrieForle strlen returns the length and does not compare

Answer 6

Hape oops, that was a typo. Corrected.

Answer 7

Thank you so much!