Tell me, how this code to write shorter?

Question

let c = ['twenty ', 'thirty ', 'forty ', 'fifty ', 'sixty ', 'seventy ', 'eighty ', 'ninety ', 'hundred']
function digital(numberThree) {
for (let k = 1; k <= c.length + 100; k++) {
k = numberThree;
if (numberThree == k) {
k -= 20;
console.log(c[k])
break;
}

}
}
digital(20)
// if will digital(30), that will be console.log(c[k - 9]), if will digital(40), that will be console.log(c[k - 18]), if will digital(50), that will be console.log(c[k - 27])

Answer 1

I don't know what you're trying to accomplish but your loop will only do a maximum of 1 iteration because your k variable is assigned a value and your condition to break the loop is hit immediately.

The following will behave exactly like your digital function for-loop and be much shorter:
let c = ['twenty ', 'thirty ', 'forty ', 'fifty ', 'sixty ', 'seventy ', 'eighty ', 'ninety ', 'hundred']
function digital(numberThree) {
console.log(c[numberThree - 20])
}

These comments don't match your digital function implementation at all:
// if will digital(30), that will be console.log(c[k - 9]), if will digital(40), that will be console.log(c[k - 18]), if will digital(50), that will be console.log(c[k - 27])

If instead, you just want digital(20) to print "twenty", digital(30) to print "thirty"..., this would work:
let c = ['twenty ', 'thirty ', 'forty ', 'fifty ', 'sixty ', 'seventy ', 'eighty ', 'ninety ', 'hundred']
function digital(num) {
console.log(c[(num - 20) / 10]);
}

Answer 2

Josh, thanks)