Check this program and predict your outputs.

Question

Please Explain the program execution ...
https://code.sololearn.com/cKFw6Sv2TE3x/?ref=app

Answer 1

Your program has some syntax and logical errors.
After removing this errors i get the output: 4
Because &arr[4]=4 and &arr[0]=0 so simply 4-0=4

Answer 2

Amaresh Ray
I think the size of integer in the given compiler is 4, that's why you got the difference of 16 between the addresses of 1st and 5th element.(Each element takes 4 which acts as space of an element and defined by same address , because one element is defined by a single address not more than one)

Answer 3

hey Amaresh Ray
you get answer " 4 " because you are using pointers arithmetic !
if you want output in simple or reak byte difference then ,
1. multiply by size of data type to difference of addresses (result)
2. or simply multiply by " 4 " in your case , (because of integer array)

[remove one extra curly braces above the return and use long int " %ld " ]

Answer 4

There is one extra curly braces in your program use ld instead of %d
It will work without warnings
#include <stdio.h>

int main()

{

int arr[5]={10,20,30,40,50};

printf("%ld",&arr[4]-&arr[0]);

return 0;
}

Answer 5

I assume that &arr[0]=0 so &arr[4]=4 hence the difference is 4 because array allocates in contiguous manner.

Answer 6

Hey Akash Singh Your answers is correct But still I have some doubt regarding this bcz I am getting value of &arr[4] and &arr[0] is something which has difference of 16.
I'm trying to find this way:-->

#include <stdio.h>

int main(){

int arr[5]={10,20,30,40,50};

printf("%ld %ld\n",&arr[4], &arr[0]);

printf("%ld",&arr[4]-&arr[0]);

return 0;
}

Answer 7

Akash Singh
how you calculated &arr[4]=4 and &arr[0]=0 ?