Why is the output 2?

Question

#include<stdio.h>
int main()
{
int a[3] ={2,1,0};
printf("%d",a[a[2]]);
}

Answer 1

a[2]=0,and a[0]=2

Answer 2

Divide the question into simpler terms and go step by step

Answer 3

See printf("%d",a[a[2]]);
Here a[2] will be calculated first because it is present inside . After calculation answer=0(a[2]). Now the value of a[0] =2

Answer 4

Sorry
Can you elaborate ?

Answer 5

Thanks mate
Got it!!

Answer 6

Hridoy Banik My pleasure