how can i solve this?

Question

Hey guys
why I have this error in lines 22, 26, 30, and 34?
error : subscribted value is neither nor pointer nor vector
#include <stdio.h>
void StrStat(Str);
int main()
{
char StrReza[100];
fgets(StrReza,100,stdin);
StrStat(StrReza);
return 0;
}
void StrStat(Str)
{
int a;
a = strlen(Str);
int baseda;
baseda = 0;
int biseda;
biseda = 0;
int adad;
adad = 0;
for(int i=0;i<a;i++)
{
if(Str[i]==97 || Str[i]==101 || Str[i]==117 || Str[i]==111 || Str[i]==105 || Str[i]==65 || Str[i]==69 || Str[i]==79 || Str[i]==85 || Str[i]==73)
{
baseda++;
}
else if(Str[i]>=65 && Str[i]<=90 && Str[i]!=65 && Str[i]!=69 && Str[i]!=79 && Str[i]!=85 && Str[i]!=73)
{
biseda++;
}
else if(Str[i]>=97 && Str[i]<=122 && Str[i]!=97 && Str[i]!=101 && Str[i]!=117 && Str[i]!=111 && Str[i]!=105 )
{
biseda++;
}
else if(Str[i]>=48 && Str[i]<=57)
{
adad++;
}
}
printf("%d\n%d\n%d",baseda,biseda,adad);
}

Answer 1

hey reza change following
1.include <string.h>
2.void StrStat(char []);
3.void StrStat(char*Str)

Answer 2

Str is a string.... in line 21, in the if statement you are comparing string with integer....thats why its an error...

Answer 3

Thirt13n
Yeah it's working now
Thanks a lot

Answer 4

Calvin Thomas
Counting vowels and consonants and numbers in a string

Answer 5

Here's a simple solution:

#include <stdio.h>

void isalpha(char k);
void str_stat(char *txt);

int main() {
char buf[50];
fgets(buf, 50, stdin);
str_stat(buf);
return 0;
}

void isalpha(char k) {
return k > 64 && k < 91 || k > 96 && k < 123;
}

void str_stat(char *txt) {
int count_1 = 0, count_2 = 0, count_3 = 0;
char vowels[] = "aeiou";
for (int i=0;txt[i];i++) {
for (int j=0;j<6;j++) {
if (txt[i] == vowels[j]) {
count_1++;
break;
}
count_3 += j > 4 && isalpha(txt[i]);
}
count_2 += txt[i] > 47 && txt[i] < 58;
}
printf("No. of vowels = %d\nNo. of consonants = %d\nNo. of numbers = %d", count_1, count_3, count_2);
}

// Hope this helps

Answer 6

Calvin Thomas
Yeah it's simpler
Thanks
It helped me

Answer 7

@Md. Mursalatul lslam Pallob
I changed it to Str[i]=='a' and like this but I have this error again.

Answer 8

reza What should this code do?