Can someone give me a code of python in this question 🙏🏼

Question

Write a program that displays multiple of 3 from 300 to 100

Answer 1

First try then if there is problem on the code ask

Answer 2

n=0
for n in range(300,100,-1):
if n%3==0:
print(n)
n=n+3

Yes this is working it gives the answer...indent below the print to get answer

Answer 3

Post your attempt first

Answer 4

Disha Jain i edited your code a little . added -1 as 3rd parameter to range and did proper indent to n+=3 line .

n=0
for n in range(300,100,-1):
if n%3==0:
print(n)
n=n+3

Answer 5

I think this is more correct...

for n in range(300, 100 - 1, -1):
if n % 3 == 0:
print(n)

Answer 6

n=0
for n in range(300,100):
if n%3==0:
print(n)
n=n+3

I tried this...but this give me no output

Answer 7

Md Sayed thankuu so much

Answer 8

Hi😊

try adding steps in the range function☺.

adding negative step will reserve movement, else you will find no output.

range(300, 100, -1)

if you want to learn more look at this ----->

"The Python range() Function (Guide) – Real Python"
https://realpython.com/python-range/

Answer 9

print(*[n for n in range(300,100,-1) if n%3==0])

Or since the start of 300 is divisible by 3 you can step by -3:

print(*range(300,100,-3))

Answer 10

Disha Jain Here's the solution as a one-liner:

for x in range(300, 100, -3): print(x)

Or

print(*range(300, 100, -3), sep='\n')

# Hope this helps

Answer 11

Just use the step value.
for i in range (300,100,-3) :
print (i)
That's it .👍