What am I doing wrong?

Question

print("Are you familiar with artificial intelligence and bots? Please pick from the following list:\n ")
fam_w_AIbts_list = ("I can make them", "Decently familiar", " Somewhat familiar", "Not sure", "Not too familiar", "Just barely familiar", "Not at all familiar")
print(fam_w_AIbts_list)
user_fam_w_AIbts = input()
if user_fam_w_AIbts in fam_w_AIbts_list[0, 2]:
print("Oh nice!")

The above code gives me an error of "tuple indices must be integers or slices, not tuple." I am new :|

Answer 1

maybe you meant to do list slicing, so the separator of indices in bracket must be the colon, not the comma:

[0:2] instead of [0,2]

Answer 2

read my last post ;P

slicing return a sublist of elements...

you could also use a range object, to make a list (generator -- could be iterated only once) of indices to test if user input is inside (user input must be also converted to number):

if int(user_input) in range(0,3)

or range(1,4) if indices start at 1...

you can store a "real" list in a variable to use it more than once:

indices = list(range(0,3))

Answer 3

Dea Mer

my question was: what do you expect by doing list[0,2] ?

... as inside brackets of a list, the comma is interpreted as tuple items separator, so you're doing list[(0,2)] wich is illegal as indices must be either integer (alone) or slice (2 or 3 integers colon separated)...

Answer 4

list slicing work as: list[start:stop:step]

start is the starting index (included)
end is the ending index (not included)
step is the step to skip indexes (optional)

Answer 5

the user input should match exactly the string in the sliced list (case sensitive -- you could lower or upper case all string to match case unsensitive)

to test if user input is one of the 3 first elements, you must list[0,3]...

Answer 6

if you input user for the index of the element, you must decide if it is supposed to start at 0 or at 1...

then you only have to test if 0 <= int(user_input) <= 2 (or 1 <= int(user_input) <= 3, depending on your initial choice), as inputs are string if you doesn't convert them to another type ^^

Answer 7

No more error but it's skipping "Oh nice!" now

Answer 8

what's the purpose of your code?

I simply guessing that you want to check if user input was inside the first two elements of the list ^^

Answer 9

Oh that's just a sample; I'm trying to make a chatbot thing

Answer 10

Ohhh, I see. I'm trying to get "Oh nice!" to print if the user's input matches indices 0, 1, and 2 of fam_w_AIbts_list. I no longer get the error, but Pydroid is skipping the last print statement even when the input is correct.

Answer 11

Yeah, I fixed that. Do you know how to get "Oh that's nice!" to print

Answer 12

Input matches string. I did
famAIbts_list = ["I can make them", "Decently familiar", " Somewhat familiar", "Not sure", "Not too familiar", "Just barely familiar", "Not at all familiar"]
print(famAIbts_list[0,3])
and got the "indices must be string or integer, not tuple" error again. However, when I do
print(famAIbts_list[0:3])
it displays the values

Answer 13

Do I need a for loop?

Answer 14

Oh didn't see, my bad. I think I got it, thank you so much!!! Very much appreciated 😁