What is the problem with this code?

Question

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt();
//введите код сюда
do{
if (number % 3 == 0){
continue;
}
System.out.println(number);
number--;
} while (number > -1);
}
}

It returns execution times out, but I don’t understand why. Can you help me please?

Answer 1

well, when your code encounter a number divisible by 3 he never change its value, so you will never end the loop ^^

instead of == 0, use !=0 and replace 'continue' by moving here your print statement ;P

Answer 2

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int number = read.nextInt();
do{
if (number % 3 != 0){
System.out.println(number);
}
number--;
} while (number > -1);
}
}

Answer 3

Let's assume the number is 6 (multiple of 3)
Then
number % 3 == 0 // becomes true

And skip to next value
The next time number DIDN'T CHANGED
number is still 6 and number % 3 == 0 is still true. This creates a infinite loop.

Add number-- before 'continue' statement.