please help me to find size of array.........

Question

int arrSize = sizeof(arr)/sizeof(arr[0]);
//OK it works fine for me,I understood

int arrSize = *(&arr + 1) - arr;
//I am not able to get it properly

As far as I got it, I think (&arr+1) is the address of address which reflects the address of next to whole 'arr'.......
dereferencing it will give us back the address of arr end but how?
This is all I can understand ulta sidha...

please help me to get it.....................

Answer 1

Martin Taylor thanks a lot buddy to make it clear to me.........

Answer 2

Martin Taylor Looks like its time for me to revisit some pointer arithmetic concepts in order to enter the esoteric club 😬

Answer 3

Infinity bro i am talking about (&arr+1)
Not (arr+1)

Answer 4

Infinity bro please describe me how 2nd method provides size of an array???

Answer 5

Infinity bro you were wrong ..
arr+1 means memory address of array element at index 1

*(arr +1 ) means arr[1]

Answer 6

I never said `arr+1` is equivalent to `*(arr+1)`