Python List Comprehension

Question

Code should output only consonants< I managed to omit only 'a', want to omit other vowels too (e,i,u etc) but doesn't work --> I tried like this ...if letter != 'a', 'u','e'

Help me what I am doing wrong?

word = input()
print([letter for letter in word if letter != 'a'])

Answer 1

Adilet Kambarov ,

you are very close to get it.

instead of using the current if clause inside the comprehension, you can use this one:

print([ ......if letter not in 'aeiou '])

this results in a list of single letters. so all vowels and spaces will not be in the output.

if punctuation also should be excluded, put them also to the string with the vowels. a collection of punctuation characters can be get after importing module string.
using "string.punctuation" gives you all these characters.

so finally it could look like:

print([.....if letter not in 'aeiou ' + string.punctuation])

Answer 2

# with regular expression that's quite easy:

import re

regex = re.compile("[^b-df-hj-np-tv-z]",re.I)

new_text = re.sub(regex, "", text)

# and if you want to only remove vowels, just change regex:

regex = re.compile("[aeiou]",re.I)