Letter counter

Question

Given a string as input, you need to output how many times each letter appears in the string.
You decide to store the data in a dictionary, with the letters as the keys, and the corresponding counts as the values.
Create a program to take a string as input and output a dictionary, which represents the letter count.

Sample Input:
hello

Sample Output:
{'h': 1, 'e': 1, 'l': 2, 'o': 1}

text = input()
dict = {}
#your code goes here
for letter in text :
key =str (letter )
value = text .count(letter )
print ({key : value })

Plz help🤪

Answer 1

Try this
text = input()
dict = {}
#your code goes here
for char in text:
counts = text.count(char)
dict[char] = counts
print(dict)

Answer 2

You've almost got it, but your code only prints the last key: value pair created. You need to create your dictionary, pair by pair, then print it.

The easiest way is using a comprehension like this (using set() eliminates duplicates):

letters = {letter: text.count(letter) for letter in set(text)}
print(letters)

Here's an example

https://code.sololearn.com/c5SZz6Ecsnqz

Answer 3

# the most efficient (and shortest) way would be to use Counter object from collections module:

from collections import Counter

print(dict(Counter(text)))

Answer 4

Thank u all😇

Answer 5

text = input()
dict = {}
count = 0
for i in text:
count = text.count(i)
dict[i] = count
print(dict)

Answer 6

def letter_count(text, letter):
#your code goes here
return text.count(letter)

text = input()
letter = input()

print(letter_count(text, letter))

Answer 7

Can you tell what output u want give more details about Question u have posted code only

Answer 8

David Ashton why does it print only the last pair?