Help me stuck in pointer [C program] why *s=115 showing while s=4210688

Question

Int main (){
Char *s="solo";
Printf("%d",*s);
Printf("%d",s);
Char *p=s;
Printed("%c%c", *(p+3),s[1]);
Return 0;
}

Answer 1

When a char is printed by an integer format specifier, it's ASCII value is printed.
*s is a char i.e., 's' and ASCII value of 's' is 115. (try this: printf("%d", 's');)
Now why printf("%d", s); gives 4210688. It is because s is a pointer and it stores an address. 4210688 was the address stored by the pointer s.

string:
's' 'o' 'l' 'o'
4210688 4210689 4210690 4210691

Answer 2

ａｂｈｉｎａｖ well explained answer thank you