Can anyone fix all the problems in this code?

Question

#include<studio.h>
#include <string.h>
int main();
{
float fh, cl;
int 3choice;
printf("\n1: Convert temperature from Fahrenheit to Celsius.");
printf("\n2: Convert temperature from Celsius to Fahrenheit.");
printf("\nEnter your choice(1, 2”:);
scanf("%d",choice);
if(choice = =1);{
printf("\nEnter temperature in Fahrenheit: ");
scanf("%lf",&fh);
cl = (fh - 32) / 1.8;
printf("Temperature in Celsius: %.2f",cl);
}
else if ( choice = 2 ){
printf("\nEnter temperature in Celsius: ");
scanf("%f",&cl);
fh= (cl*1.8)+32;
printf("Temperature in Fahrenheit: %.2f",fh);
}
Else ( choice = =3) {
printf("\nInvalid Choice !!!");
}
return 0;
}

Answer 1

Are you sure you have written this code. In your code i have seen lots of mistakes somewhere u put bracket unnecessary u dont need to put anywhere your if esle is misleading.
You have not included headerfile properly in if condition u written semicolon how next statements will execute your 3choice variable is not valid in scanf choice here u forget ampersand in scanf u have written %lf for float.
In else statement your E should be small

Answer 2

#include<stdio.h>
#include <string.h>
int main()
{
float fh, cl;
int choice;
printf("\n1: Convert temperature from Fahrenheit to Celsius.");
printf("\n2: Convert temperature from Celsius to Fahrenheit.");
printf("\nEnter your choice(1, 2:)");
scanf("%d",&choice);
if(choice ==1)
{
printf("\nEnter temperature in Fahrenheit: ");
scanf("%f",&fh);
cl = (fh - 32) / 1.8;
printf("Temperature in Celsius: %.2f",cl);
}

else if( choice == 2 ){
printf("\nEnter temperature in Celsius: ");
scanf("%f",&cl);
fh= (cl*1.8)+32;
printf("Temperature in Fahrenheit: %.2f",fh);
}
else
{
printf("\nInvalid Choice !!!");
}
return 0;
}