Why does the test cases 3 and 5 are not working properly????

Question

n = input().split(" ")
a = 0
for i in n:
b = len(i)
a = a+b
x = len(n)
print(round(a/x))
Here is the question:
You are in a college level English class, your professor wants you to write an essay, but you need to find out the average length of all the words you use. It is up to you to figure out how long each word is and to average it out.

Task:
Takes in a string, figure out the average length of all the words and return a number representing the average length. Remove all punctuation. Round up to the nearest whole number.

Input Format:
A string containing multiple words.

Output Format:
A number representing the average length of each word, rounded up to the nearest whole number.

Sample Input:
this phrase has multiple words

Sample Output:
6

Answer 1

Shaik.Shahir ,

to get a useful help from the community, please also provide a clear task description.

thanks!

Answer 2

Shaik.Shahir ,

the task description says, that the output has to be rounded up to the nearest whole number, but you applied round(). this will result in rounding up OR down depending on the value you wanted to process.
to do it according the description you need to apply the ceil() function. to do so, you need to import the "math" module.

you also have to remove all punctuation characters.

happy coding and good success!

Answer 3

Shaik.Shahir ,
from which python tutorial is this task?
the removing of the punctuation is still missing...

Answer 4

When I am running this code though I am getting correct output it failes in test case 3 and 5 and I do not know why??

Answer 5

import math
n = input().split(" ")
a = 0
for i in n:
b = len(i)
a = a+b
x = len(n)
print(math.ceil(a / x))
But when I try this I am getting the test caes 1 get failed

Answer 6

Shaik.Shahir Your code missing :
1)Remove all punctuation.
2) Round up to the nearest whole number.
i think it asking round up so you may need ceil(a/x)

Answer 7

Shaik.Shahir you have remove punctuation marks from input if any first.. and count remainings.
Ex: abcd@efg to abcdefg

Answer 8

Okkk

Answer 9

Then what about this
import math
n = input().split(" ")
a = 0
for i in n:
if i not in "@#&+()/?":
for x in i:
b = len(x)
a = a+b
x = len(n)
print(math.ceil(a/x))

Answer 10

https://code.sololearn.com/cg7v4LCRF7Gs/?ref=app

Answer 11

import math
import re

w = re.sub(r"\W", " ", input()).split()
a = sum(map(len, w))/len(w)
print(math.ceil(a))

# split default separator is space
# regex \W match not word chars (ascii alphanumerics + underline)
# re.sub replace pattern with substitute string in input string
# sum return sum of iterable
# map return iterable mapped with function

Answer 12

if I not in "@#&+/?" : It won't work because here I have values "words" , not individual charecters. But you need charecters in 'i' here. So take it into inner for loop, so x will have charecters only and then
if x not in"@#&+()/?"

Works fine . Again here you missing some punctuations "%$!.." add those..

edit: Shaik.Shahir
check this only after your tried again

import math
n = input().split(" ")
a = 0
for i in n:
for x in i:
if x not in "@#&/?%!quot;:
#b = len(x)
a = a+1
x = len(n)
print(math.ceil(a/x))

Answer 13

u=input("")

is_lower = u.lower()
is_lower1 = is_lower.split()

length=len(is_lower)
total=len(is_lower1)

print("Average word length : " , length/total)

try this