Cannot get this program to return the average of 3 numbers

Question

function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

avg(num1, num2, num3);
console.log(average);

}

//complete the function
function avg(num1, num2, num3)
{
average = (num1 + num2 + num3) /3;
return average;
}

Answer 1

And also dont forget to call main function with main()

Answer 2

Thank you, I thought I was calling the function here with avg=(num1,num2,num3);
and I guess I was but as you said without assigning the value to "average"
I guess outside of the function avg, the variable average loses scope.
I think if I had console.log(average) within function avg it would have worked

Answer 3

I just tried it without assigning a return value at all and it worked but of course part of this task is to return a value
function main() {
var num1 = parseInt(readLine(),10);
var num2 = parseInt(readLine(),10);
var num3 = parseInt(readLine(),10);

var average;

//assign the average value to the variable average

avg(num1, num2, num3);
//console.log(average);

}

//complete the function
function avg(num1, num2, num3)
{
average = (num1 + num2 + num3) /3;
console.log(average);
}