Help me to fix the problem ??

Question

a = input().lower()
for i in "aeiou":
a = a.replace(i,i)
print(a)
You are given a string 'S'. Your task is to reverse the vowels in the string while keeping the consonants unchanged.

Answer 1

Hi Shahir!
Nice concept.
Let's check I understood your question correctly.

Input: Shahir
Output: shihar
Am I correct?

Answer 2

that is my basic try:

inp = input().lower()
vowels = "aeiou"
vow_lst = [i for i in inp if i in vowels]
for char in inp:
print(vow_lst.pop(),end="") if char in vowels else print(char,end="")

vow_lst containes a list of all occuring vowels in the sequence they appear. when printing, pop() is used which picks and removes always the last vowel of the vow_lst from the end of the list, so it is accessing them in reverse order.

Answer 3

one possible solution:

a=input()
av=""
for i in a:
if i in "aeiouAEIOU": av+=i
b=""; c=0
for i in a:
if i in "aeiouAEIOU":
c+=1
b+=av[-c]
else:
b+=i
print(b)

Answer 4

My solution

a = input().lower()
l = []
e = ""
for i in a:
if i in "aeiou":
l.append(i)
for i in a:
if i in "aeiou":
e += l.pop()
else:
e += i
print(e)

Answer 5

a=input()
b=list(a)
g=""
c=[]
vovel="aeiou"
for i in b:
if i in vovel:
c+=[a.index(i)]
g=i+g
a=a.replace(i,' ',1)
for l,i in zip(g,c):
b[int(i)]=l
print(*b)

Answer 6

This is my try:
https://code.sololearn.com/c5KsxHR3iVgj
Explanation:
First, it takes all the vowels in a list from the string in a reverse way with list comprehension, and then again iterates the string and adds to a list if it's a non-vowel otherwise if it's a vowel it takes the value from the reversed vowel list and adds it and at last print the list as a string.

Answer 7

Shahir ,

replacing "i" with "i" does not change anything.

can you please make an output sample for the input sample: "klaxiuaaz" ?

Answer 8

Here's a one-liner possibility:

print("".join(map(lambda x: b.pop() if x in "aeiou" else x, (a := input().lower()) + str(b := [x for x in a if x in "aeiou"]) * 0)))

# Hope this helps
# Happy coding!

Answer 9

Sunday Olorunfemi ,

as i understand, the vovels will be handled like:

_a_iia_eau_oooo # <<<< input
_o_ooo_uae_aiia # <<<< output

the underscore can be seen as any other letter or number

Answer 10

Yes python Learner that's how the output should

Answer 11

Harshit Jawla I paste my code, but Not fully pasted

Answer 12

s = list("hello heres my solution")
i,j = 0,len(s)-1
while True:
while i<len(s)-1 and s[i] not in "aeiou":
i += 1
while j>=0 and s[j] not in "aeiou":
j -= 1
if i >= j:
break
s[i],s[j] = s[j],s[i]
i, j = i+1, j-1
print("".join(s))

Answer 13

Could you please explain me your code once

Answer 14

Calvin Thomas your oneliner code did not work.

Answer 15

Use two variables i,j in a loop, let i go forwards from 0 and j go backwards from the end. Move each one until you meet a vowel character, then swap those characters, and repeat. Stop when i,j pass each other.

Since its an exercise, i will just let the implementation details for you to figure out

Answer 16

Harshit Jawla
There is no v variable in my code.
c and g I walk on the input str and add its vowels to the variable g and add the index to variable C.
Line 6 indentation is because we're in the for loop.

Answer 17

Amir see I mentioned that for your previous code, not your edited one

Answer 18

Lew!S✨ perfect 🤘

Answer 19

yes

Answer 20

Shahir Apart from certain minor differences, the explanation pretty much simplifies to Lothar's explanation given above.