You need to change the code to skip the even numbers, so that the logic only applies to odd numbers in the range.

Question

The given code solves the FizzBuzz problem and uses the words "Solo" and "Learn" instead of "Fizz" and "Buzz".
It takes an input n and outputs the numbers from 1 to n.
For each multiple of 3, print "Solo" instead of the number.
For each multiple of 5, prints "Learn" instead of the number.
For numbers that are multiples of both 3 and 5, output "SoloLearn".
You need to change the code to skip the even numbers so that the logic only applies to odd numbers in the range
This is my code:
n = int(input())
for x in range(1, n):
if x % 2 == 0:
continue #To skip even numbers
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)
So, here when I run the output: Test 1- passed
Test 2: failed

I'm unable to find the error of Test 2 since it's locked.

Answer 1

Shree Harini
You didn't write a bit of code for %3 &%5 -> Sololearn

See if this helps, your code with a tweak.
Take note of the list slicing within your range call

n = int(input())
for x in range(1,n,2):
if x % 15 == 0: # %3 & %5
print("Sololearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)

Answer 2

Shree Harini
A friend of mine just pointed out that the challenge requires an output of numbers from 1 to n.

So I need to tweak my tweak.
🤣😂

for x in range(1, n+1, 2) # better

Answer 3

Please search before postng

https://www.sololearn.com/Discuss/2543653/?ref=app

Answer 4

This is the correct code:

n = int(input())

for x in range(1, n):
if x % 2 == 0:
continue
elif x % 3 == 0 and x % 5 == 0:
print("SoloLearn")
elif x % 3 == 0:
print("Solo")
elif x % 5 == 0:
print("Learn")
else:
print(x)