#include <stdio.h> int main() { int x=4,y,z; y=--x; z=x--; printf("%d",x); return 0; } output value and why ??

Question

#include <stdio.h>

int main() {
int x=4,y,z;
y=--x;
z=x--;
printf("%d",x);
return 0;
}

Answer 1

ahh, how bigger your balls are by posting the whole code in the title, now the forum looks ridiculous

the output would be 2 since you're decrementing x,
y and z doesn't have any initial value stored

Answer 2

y = --x; // now x = 3
z = x--; // next time x = 2

So
printf gives 2