java shape class

Question

My code fails at the third locked test case and I can't view it.
What is the problem?
It contains three classes (Shape, Square, and Circle) and we need to calculate the area of each shape.
This is the link to code:
https://code.sololearn.com/cvE90UeATprg
This is the whole code:
import java.util.Scanner;

abstract class Shape {
int width;
abstract void area();
}
class Square extends Shape{
public Square (int width ){
super.width =width;
}
public void area(){
System.out.println((int)Math.pow(super.width ,2));
}
}
class Circle extends Shape {
public Circle (int width){
super.width =width;
}
public void area(){
System.out.println( Math.PI*Math.pow(super.width ,2));
}
}

public class Program {
public static void main(String[ ] args) {
Scanner sc = new Scanner(System.in);
int x = sc.nextInt();
int y = sc.nextInt();

Square a = new Square(x);
Circle b = new Circle(y);
a.area();
b.area();
}
}
Which one is correct? super.width or this.width

Answer 1

Nobody can see your code. For this you should save it on SL Playground and link here.

Answer 2

You should to replace
„super“ with „this“
and
„Math.pow“ with „this.width * this.width“.

Answer 3

JaScript What is wrong with super and Math.pow? why super is not correct? width is defined in parent class so when I want to initialize it I think super is needed.

Answer 4

The answer to the second question

Answer 5

Does it work what I have shown?
PS. For more information please see advanced tutorials, books or maybe try the web search.
Happy coding.

Answer 6

I edited the URL

Answer 7

Code Below Passed All Test. 💯%

class Square extends Shape{
public Square (int width ){
this.width =width;
}
public void area(){
System.out.println(width*width);
}
}
class Circle extends Shape {
public Circle (int width){
this.width =width;
}
public void area(){
System.out.println(Math.PI*width*width);
}
}