Why is this false?

Question

int i = 5,j =7 k=9
j<5 || i <=7 && k==10;

Answer 1

@Samira

Let x be true,

x && !x
true && !true
true && false
false

Let x be false,

x && !x
false && !false
false && true
false

This means that x && !x will always be false.

Answer 2

When we substitute the variables for their value instances:

7 < 5 || 5 <= 7 && 9 == 10

Remember that && has higher precedence than ||, hence:

false || true && false
false || false
false

Answer 3

int x = 3;
if(x && !x) cout << "true";

always be false
3 is true
!3 is false
So
(true && false)

Answer 4

Because k is not 10, simple as that.
&& means AND
|| means OR

AND I need k to be 10.

Answer 5

Ah......really?
I think it was j<5 make it return false
After I flip it into j>5 condition return true

Answer 6

AND operator has a higher precedence than OR operator
http://en.cppreference.com/w/cpp/language/operator_precedence
j(7)<5 || (i(5) <= 7 && k(9) == 10)
j(7)<5 || (true && false)
false || false
false

Answer 7

Thank you all so much for helping!!
Why would something like this:
x && !x
be false then??

Answer 8

Thank you all soo much! That was very helpful, I appreciate it :D