What's wrong with the C code?

Question

Original question: https://www.sololearn.com/coach/54?ref=app

Basically, I'm trying to find how many times a character occurs in a string.
So my approach was to, loop through the string, set 'i' to the variable 'ch', then loop through the string again (nest loop), comparing if 'ch' is == 'i', and if it is, increment 'count' varible, otherwise do nothing.
Then after everything is done, check if 'count' variable > 1, if it is, output "Deja Vu", else "Output".
But my code isn't working well because it outputs "Deja Vu" on every test case.
Hope y'all understand what exactly am trying to say 😔.

My C CODE:
#include <stdio.h>
#include <string.h>

int main() {

char str[1000];
scanf("%s", str);
int i, j, count = 0;
char ch;

for (i = 0; i < strlen(str); i++) {
ch = i;
for (j = 0; j < strlen(str); j++) {
if (ch == j) {
count++;
}
}
}

if (count > 1) {
printf("Deja Vu");
} else {
printf("Unique");
}

return 0;
}

Answer 1

There is no need of nesting of loop, you just have to check whether a character is repeating it self, and you can go with:
for(i = 0; i<strlen (str); i++){
if (str[i] == str [i+1]){
count++;
break;
}
}
if(count > 1)
printf ("Deja Vu");
else
printf ("Unique");