Can we do this range option on string?

Question

I tried but failed... I wrote the code like.... A="dragon" A=list(range(1, 7, 2))Print(A)EXPECTED OUTPUT-['d', 'a', 'o']Actual output -[1, 3, 5]

Answer 1

Your question is answered...
But now let's see why you got 1,3, 5 for your code...
-------------
#you initialized A
A="dragon"
#you reinitialized A with ranges... Previous value gets overwritten
A=list(range(1,7,2))
#Now, A =[1,3,5] since, from 1 till 7(excluding 7) with interval of 2
print(A)
#that's why you got 1, 3, 5
-------------
#Alterntive Solution... Should work.. But not working.. -,-
A="dragon"
for i in range(0,6,2):
A[i/2]=A[i]
del(A[3],A[4],A[5])
print(A)

## Alternative Solution 2, Works perfectly
A="dragon"
A=A[::2] #Using slice like said by Red Ant
print(A)
#Output : dao

##Alternate solution 3, works fine
A=["d","r","a","g","o","n"]
B=[]
for i in range(0,6,2):
B.append(A[i])
print(B)
# output : ["d","a","o"]

Answer 2

If you specifically want to use range, there is a way. But you will have to create another list.
a="dragon"
b=[" "]*3
a=list(a)
b=list(b)
j=0
for i in range(0,6,2):
b[j]=a[i]
j+=1
print (b)

If you don't want to use another variable then directly print(a,end=" ") inside Loop, but then you won't get a list.

Answer 3

you can use list slices ( lesson More Types/List slices ) on the strings to achieve something like that. so to get your desired output you can use:
A[0::2]
which basically means take first character, then every other till the end of the string.