Return statement in javascript

Question

Why this code is returning value of ..a
And not ...a*2

Var input=[2,6,9,0]

function removeEven(input) {
return input.filter(function(a){
if(a%2 !==0){
return a* 2
}
})
}
Console.log(removeEven(input))

Answer 1

Riya Chawla

Simply put, the filter function returns either true or false. Since you're trying to return integers, everything will be treated as true unless it's 0. Because integers are truthy values by default in JavaScript, change that line of your code to what DavX has provided

For more information on truthy/falsy values:

https://developer.mozilla.org/en-US/docs/Glossary/Truthy#:~:text=All%20values%20are%20truthy%20unless%20they%20are%20defined,boolean%20contexts%2C%20and%20thus%20execute%20the%20if%20block%29%3A

My apologies for the lengthy link 😉

Answer 2

Riya Chawla

To start with you don’t use !== to check ‘not equals’. Simple use !=

I guess you are trying to remove even numbers from a list? Here’s how you can do this:

var testInput = [2, 6, 9, 0];

function removeEven(num) {
return num % 2 != 0;
}

console.log(testIn.filter(removeEven));

This returns:
[9]

Answer 3

The filter() method creates an array filled with all array elements that pass a test

What happens here is :
Input is an array with 2,6,9,0

Now u are using filter method to filter an array means u are getting the number which is noteven
Coz any number with is divisible by 2 returns 0 is odd

it will not change the original array

Answer 4

Nick thanks