How do you get the smallest integer in a list without using the min() built-in function and also its index?

Answer 1

Use a for loop to go through each element. Test if it is less than a variable "min." If it is, replace "min" with that number and continue until you have gone through all of the elements.

Answer 2

what J.G. said

Answer 3

for loop with "enumerate" function will help you get both min value and its index at the same time.

Answer 4

nums = [23,18,45,2,9]
x = sorted(nums)[0]
print(x,nums.index(x))

Answer 5

Implement a sort algorithm (quick sort, bubble sort, binary sort)