The expression 2**2**3 is evaluated as: (2**2)**3? True or False

Question

answer is : False
But this is True, as much as i know, if two operators have same precedence the the left one evaluate first. eg: 5%4*2 --> (5%4)*2 --> (1)*2 ---> 2
not 5%(4*2) ---> 5%8 ---> 5

Answer 1

Most operators are indeed left associative, but ** is right associative, mainly because
(a**b)**c == a**(b*c)
While a**(b**c) doesn't have an easy identity

Just like we don't see a*b+c as a*(b+c) == (a*b) + (a*c),
but as (a*b) + c

Answer 2

I think, it is False also. Cause,
2**2**3 = 2^2^3 = 2^8 = 256
(2**2)**3 = (2^2)^3 = 4^3 = 64

You see the result of this expressions and these are not equal. So, the answer is False.

I hope, it's clear.
Happy coding!

Answer 3

operator precedence for ** is from right to left in your case . You can google "operator precedence in python" and go through the offical docs for info.