New Driver's License (How to do this)?

Question

You have to get a new driver's license and you show up at the office at the same time as 4 other people. The office says that they will see everyone in alphabetical order and it takes 20 minutes for them to process each new license. All of the agents are available now, and they can each see one customer at a time. How long will it take for you to walk out of the office with your new license?

Task
Given everyone's name that showed up at the same time, determine how long it will take to get your new license.

Input Format
Your input will be a string of your name, then an integer of the number of available agents, and lastly a string of the other four names separated by spaces.

Output Format
You will output an integer of the number of minutes that it will take to get your license.

Sample Input
'Eric'
2
'Adam Caroline Rebecca Frank'

Sample Output
40

Answer 1

#this may help you and I have done in python, don't mind :)
#to get myname
my_name = input()
#to get agent name
agents = int(input())
#to get all the list names of people
other_names = input()

#converting all the string to lost to sort
list_of_names = other_names.split()

#appending myname to compare
list_of_names.append(my_name)

#sorting the list as question said, work is done only in alpha order.
list_of_names.sort()

#getting the index of our name in the list...
index = list_of_names.index(my_name) + 1

#if the agents r more than index of our name, work will done soon.
#because if 5 agents r thr and thr are only 4 peoples, then my task will get sooner
if agents >= index:
result = 20

#if that's not the case start decounting the value with index and agent and finallu print the value
else:
time = index - agents
result = 20 + time * 20

#print the result finally...
print(result)

Answer 2

Thank you ☺️

Answer 3

Brian
As in the question they r asking us to sort the list of names

Answer 4

GURURAJ KL There is no requirement that says you must sort the names. The task is to determine how long it will take. You can efficiently determine the correct answer without sorting. A simple count of names less than or equal to your name gives the number to scale for the wait time.

Answer 5

myname = input()
num_agents = int(input())
other_names = list(input().split())

other_names.append(myname)
other_names.sort()

ind_myname = other_names.index(myname)+1

print('20' if ind_myname <=num_agents else (ind_myname-num_agents)*20+20)

Answer 6

There is no need to sort. Just loop through the given names and count how many names are less than or equal to yours.

GURURAJ KL's technique would give a wrong answer if there is already someone in line with the same name as you.