C++ , 21 code project. How do I fix it . I can't figure it out

Question

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
while (n>=1){

cout <<n<<endl;
n--; /*decrement after the if statement closes */

if(n%5){ //if(!(n%5))

cout <<"beep"<<endl;
}
}

return 0;
}

Answer 1

while(n>=1){
cout << n << endl;
if(!(n%5)){
cout <<"Beep"<< endl;
}
n--;
}

Answer 2

Ohh I see ..thanks Vasiliy

Answer 3

what is to be fixed ?

Answer 4

It's suppose to count down from an input 'n'

And output "beep" whenever it encounters multiples of 5

Answer 5

Vasiliy
Is it ? Didn't know
Thanks Vasiliy ..and now ?

Answer 6

I am glad that we understood each other and delete my remark.

Answer 7

But you are not getting away with one thanks ☺️
Comment on the errors in your code.

Answer 8

Vasiliy haha followed u as well

Alright

Answer 9

No, that won't work.
Why is it necessary to put an exclamation mark before the expression n%5, or how to write this condition differently?

Answer 10

Vasiliy actually it worked I tried it. And it was ur idea remember ?

If it's just n%5 . It will output "Beep" all the time the loop runs except for the multiples of five .
So to reverse it we used "!" Right ?
that's how I understood it

Answer 11

to determine a multiple of 5, it is necessary that the condition is met under which the number divided by modulus is equal to zero, that is, if 15% 5 == 0 the condition is true, since 15% 5 = 0, but if the condition is written in abbreviated form if 15% 5, it is false , and we need to make it true, for this we put before the condition "!", which means "not" and reads like "If not false then true".