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How do you rewrite the following code using only 1 repetitive structure?
for(int i=1; i<=n; i++){while(j<i){r=2*b-a; a=b; b=r; j=j+1}s=s+b}
3 Answers
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It would help to know how j is initialized (what are its possible starting values?). Also answer the same question for a, b, s and n.
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oops, sorry messed up a little, actually it is:
cin>>n;
s=0;
for(i=1; i<=n; i++){a=0; b=1; j=1;
while(j<i){r=2*b-a; a=b; b=r; j=j+1} s=s+b}
cout<<s;
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The computation can be reduced to use only s and i in the for loop. To analyze, try inserting temporary cout statements to see the behavior of the variables - especially the outcome of b after the while loop.