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How can I divide the numbers in a lisy by each other?

For example list = [10, 4, 2, 6] using a loop for? Could you write the loop, please? Thanks🙂

13th Nov 2021, 4:31 PM
Empresa X
Empresa X - avatar
3 Answers
+ 3
Empresa X , here is a sample how it can be done: # we are iterating in both loops on the same list, but each loop has its own iterator. # the output with print shows which numbers are taken and shows also the result # to output only the result use this: print(divident / divisor) lst = [10, 4, 2, 6] for divisor in lst: for divident in lst: print(f" {divident} / {divisor} = {divident / divisor}") # solution 1: in this solution all numbers will be divided by each other, also by itself. to prevent this, the code has to be modified slightly
14th Nov 2021, 9:30 AM
Lothar
Lothar - avatar
+ 6
Empresa X , itg is your task to write the code. please do a try and share it here. if you get stuck we can support you. thanks for your undestanding! here is a hint: we can use 2 nested for loops
13th Nov 2021, 4:41 PM
Lothar
Lothar - avatar
+ 1
numbers = [4, 2, 6] for x in numbers: a = x /numbers[1] numbers.pop(0) numbers.pop(0) b = a / numbers[0] print(b) At this point, I can't think of much else 😐 Lothar
13th Nov 2021, 9:41 PM
Empresa X
Empresa X - avatar