How can i create a function that finds the multiples of a number in a certain range on python ?

Answer 1

personally, I would use a generator (because I love generators)

def multiplesOf(x,max):
i=0
while i<max:
i+=x
yield i

for i in multiplesOf(10,100):
print(i)

#outputs the 10 times table up to 100

Answer 2

@Tobi Nice! I wish I knew how to make one liners like that. Hopefully the OP will vote your answer as best :)

Answer 3

def multiples(n):
for number in range (100):
if number%n == 0:
print(number)

Answer 4

Cheeky one liner for multiples of n in range(a,b):

range(a+n*int(a%n != 0) - (a%n), b, n)

Answer 5

@Aidan: Thank you! Although shorter is not always better. The cleanest solution code wise would be a list comprehension (also one line). My solution is probably the most efficient, but not too pythonic, as it is not super readable.
Best practice would be a generator, but instead of checking each number in the range, just find the first one and increase by n until you are out of the boundary.