What is this?(see code).

Question

I did notice how this 6 addition is removing 6 characters from printf.but what we call this thing.seeing for first in c challenge.
https://code.sololearn.com/ctDbL25okaZL/?ref=app

Answer 1

It's pointer arithmetic.
The expression *(a + n), where a is an array and n is an integer, is equivalent to a[n]. If you add an integer to a pointer you'll get to the location of n-th element of a.

C doesn't really have the concept of strings rather it's considered as a char pointer.

The program will look like this,
char *ptr="hello world";
printf( 6 + ptr);

which is &ptr[6] 
this address points to "world"

https://www.cs.yale.edu/homes/aspnes/pinewiki/C(2f)Pointers.html#:~:text=Pointer%20arithmetic%20and%20arrays,-Because%20pointers%20are&text=Add%20an%20integer%20to%20a,aren't%20the%20same).

Answer 2

// Watch what happens. :)

#include <stdio.h>
#include <string.h>

int main() {

char s[] = "gaurav kumar";
for (int x=0; x<strlen(s); x++) printf("%c ", s[x]);

return 0;
}

Answer 3

gaurav kumar
I don't understand it myself, but it references the index of the string.

Change the number and you will see different outputs.

Indexing starts from 0, spaces included