How to in python?

Question

If result = [name,scores]
How can I print the particular name for e specific score?

Answer 1

print([k for k,v in result.items() if v== specific_score])

If result is a dictionary with key = name and value = score)

Answer 2

Nisha

That's list not dictionary

result = [1, 2] #list
result = {1, 2} # dictionary
result = (1, 2) # tuple

Answer 3

Nisha
results = {"tom":10,"anton":14,"bertha":12}
sp_value=int(input())
print([k for k,v in results.items() if v==sp_value])

Answer 4

maybe you are trying to access a dictionary the wrong way?

dic = {"John":"30","Jake":"39"}
name = 'John'
if name in dic:
print(name + ", " + dic[name])

Answer 5

.items is not a method for lists, maybe show us your code so we can help you better?

Answer 6

David B
Here the input is name and score, then i found the second smallest number but i could not understand how to call the name for that number.

n = int(input())
result = []
all_marks = []
all_name =[]

for i in range (n):
name = input()
scores = float(input())
result.append([name,scores])
all_marks.append (scores)
all_name.append (name)
all_marks.sort()

for i in range(0,n):
if(all_marks [0+i]!=all_marks[0]):
min = all_marks[0+i]
print (all_marks[0+i])
if(all_marks [0+i+1]!= all_marks [0+i]):
break

print([i for i,v in result.items() if v==min])

Answer 7

Remember that in order to define an empty dictionary you must use curly braces {} and to add an item you would use the statement

my_dic['new key'] = 'new value'

so after you used sort on your list, to find the second minimum you would just access the second item in your list (index 1), because that's where it would be.
After that it would be easy to acces your dictionary key:value pair.

So I tried to follow what you were doing and made this:

n = int(input('N:'))
result = {}
all_marks = []
all_name = []

for i in range(n):
name = input('Name: ')
scores = float(input('Score:'))
result[name] = scores
all_marks.append(scores)
all_name.append(name) # This list will be useless and out of order after sorting your marks

all_marks.sort() # I moved this sort out of your loop so you are not sorting everytime you add an item, just 1 time at the end

key = all_name[1]
print('Second lowest score is {} with {}' .format(key, result[key]))

Answer 8

n = int(input())
result = {}

for i in range (n):
name = input()
scores = float(input())
result[name]=scores

print([i for i,v in result.items() if v==min(result.values())])

Answer 9

How to learn

Answer 10

Oma Falk result.items() showing error for list

Answer 11

It would be easiest if you used a dictionary to store your data. Then you can use min() on .values() and iterate through the dictionary to output the corresponding names

Answer 12

⭐Nakul Pasi S/0 Krishna Lal Pasi⭐ Don't copy other users answers

Answer 13

results = ["Bob",90,"William",80,"Willy",70,"kelly",60,"Keith",50]
scores = int(input("Enter Score: "))
i=len(results)
while range(i):
if scores in results:
print(f"{results[results.index(scores)-1]} Scored: {scores}")

break