C++ ticket office question 35

Question

Hi everyone, I have a question regarding arithmetic with variables of different data types. Why does my code only works if "min" was declared as a "double" and not "int"? I would wrongly get the first value of whatever is in the arithmetic statement of price. ( in this case, it is 50 instead of 44.5)

#include <iostream>
using namespace std;

int main() {
int ages[5];

for (int i = 0; i < 5; ++i) {
cin >> ages[i];
}
//your code goes here

double min = 200;
//why does this not work?
//int min = 200;
double price;

for (int i=0; i<5; i++){
if(min>ages[i]){
min = ages[i];
}
}
price = (50-(50*(min/100)));
cout<<price;
return 0;
}

Answer 1

int/int results int type only..

At least one as int/double or double/int or double/double results double value..
So in
price = (50-(50*(min/100)));
min/100 both int and if min is less than 100 then min/100 = 0 so finally it's 50-0= 50

5/2= 2 (2.5 converted back to int so 2 is results
But 5.0/2= 2.5 , all values casted to bigger type first to not loss any data..

hope it helps..

Answer 2

I understand it now with your explanation. Thank you very much.

Answer 3

You're welcome..