Random error: this 'for' clause does not guard ...

Question

They can run the code (from the retroman friend) and read the full error. When redoing it and after I finish implementing the function that frees the memory array, it compiles
https://code.sololearn.com/c5GCWfnqYjP0/?ref=app

It should only give the warning of unused variable. In the Prac Reserva_ matriz ( my code)code you can see it compile, already with the function of freeing matrix implemented.
cout suele hacer eso por su buffer al intercalarlo entre reservas y liberaciones de memoria. Hay algo similar en el bucle for?

Answer 1

You need curly braces.

#include <iostream>
#include <cstdint>
using namespace std;

#define SIZE 4
uint32_t** reserva_matriz (){
uint32_t **m = new uint32_t* [SIZE];
for(uint32_t i=0;i<SIZE;i++) {
m[i] = new uint32_t [SIZE];
}
return m;
}

int main() {
uint32_t **m;
m = reserva_matriz();
cout << m;
return 0;
}

Answer 2

yes, that's it. Thank you very much, I thought that being a short expression, the curly braces were not necessary