what is the output of this code and how??

Question

int arr[3]={40,41,42};
int *ptr=(int*)(&arr+1);
printf("%d %d", *(arr+1) , *(ptr-1));

Answer 1

Error cause you try to print a number but a pointer is supplied.

Answer 2

Cause of the ampersand '&' here is expected output:
https://code.sololearn.com/c1qq2eHR9ZP4/?ref=app

Answer 3

Martin Taylor the code he supplied outputs 41 42. When i removed the ampersand it gave expected output. I think he wants to know why

Answer 4

Slick you are right and i ve edited this code, now what is the output

Answer 5

Tell me what the output is please

Answer 6

41 42 Slick

Answer 7

could you tell me how one find the *(ptr-1) as 42. Slick
thanks

Answer 8

https://gateoverflow.in/275251/Geeksforgeeks

this post also was helpful.

Answer 9

VriddhiJain