76.2 Practice - Function Templates

Question

You need to write a function, which returns the maximum of its two parameters, and it should work for different data types (integers, doubles, etc.)
Create a function template called myMax(), which takes two parameters and returns the larger one, so that the code in main works as expected.

Sample Input
4.2
8.1

Sample Output
8.1

*Remember, the syntax for declaring a template function is template <class T>

My code is below. I have run out of ideas. Please help.

Answer 1

#include <iostream>
using namespace std;

template<class T>
T myMax(T a, T b)
{
return a > b ? a : b;
}
int main () {
double x, y;
cin>>x>>y;
int a, b;
cin>>a>>b;
cout << myMax(x, y) << endl;
cout << myMax(a, b) << endl;
}

Answer 2

#include <iostream>
using namespace std;

template<class T, class X>
T myMax(T a, X b)
{
return (T)(a > b ? a : b);
}
int main () {
double x;
int y;
cin>>x>>y;
cout << myMax(x, y) << endl;
}

This is a correct answer and runit code

Answer 3

#include <iostream>
using namespace std;

//your code goes here
template <class T>
T myMax(T a, T b)
{
return (a > b ? a : b);
}

int main () {
double x, y;
cin>>x>>y;
int a, b;
cin>>a>>b;
cout << myMax(x, y) << endl;
cout << myMax(a, b) << endl;
}

Good Luck

Answer 4

#include <iostream>
using namespace std;

//your code goes here
template <class T>
T myMax(int a, int b)
{
return (a < b ? a : b);
}

int main () {
double x, y;
cin>>x>>y;
int a, b;
cin>>a>>b;
cout << myMax(x, y) << endl;
cout << myMax(a, b) << endl;
}

Answer 5

mabey the parameters should be of the template type as well... your code only takes integers as arguments.

Answer 6

#include <iostream>
using namespace std;

template<class T>
T myMax(T a, T b)
{
return a > b ? a : b;
}
int main () {
double x, y;
cin>>x>>y;
int a, b;
cin>>a>>b;
cout << myMax(x, y) << endl;
cout << myMax(a, b) << endl;
}

Answer 7

Thanks Jay Matthews