Write a function that accepts a number as argument and returns the square of the number. For example if the number passed to the

Question

My code is working but due to the instructions I get the error which includes the function arguments. Please help!
n=int(input())
def square_num():
a = n**2
my_result = a
return my_result
print(square_num())

Answer 1

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You've used n inside your function, but where did you declare it inside the function? Your function is a seperate block that doesn't know about the variables and functions outside of it. So you need to pass in the variable n so that your function knows what n is. It'll something like the below snippet:

...
def square_num(n):
...

Hope you understood the explanation. Feel free to ask doubts if any

Answer 2

What are the instructions?
Use description place to write full question??

Answer 3

# yes, code works but there expected clean code is :

def square_num(n):
a = n**2
my_result = a
return my_result

n = int( input() )
print( square_num(n) )

Answer 4

The whole question is Write a function that accepts a number as argument and returns the square of the number. For example if the number passed to the function is 5 then your function should return 25

Answer 5

every syntax matters! my first practice with function. got my mistake,
thank you for your support! appreciate it!

Answer 6

#by taking input via argument
def square_num(n):
a = n**2
my_result = a
return my_result
print(square_num(n=int(input())))