Can someone pls help me with solution to this coding challenge?

Question

You're given a list of time intervals during which students at a school need a laptop. These time intervals are represented by pairs of integers [start, end], where 0 <= start < end. However, start and end don't represent real times; therefore, they may be greater than 24.

No two students can use a laptop at the same time, but immediately after a student is done using a laptop, another student can use that same laptop. For example, if one student rents a laptop during the time interval [0, 2], another student can rent the same laptop during any time interval starting with 2.

Write a function that returns the minimum number of laptops that the school needs to rent such that all students will always have access to a laptop when they need one.

laptopRentals(times)
Parameters
times: Array (of Array (of Integers)) - A 2D array containing the times the student would require a laptop.

Return Value
Integer - Minimum number of laptops the school needs to rent.

Examples
times Return Value
[[0,2],[1,4],[4,6],[

Answer 1

MAYOWA AKINADE ,

to give you the required help, you should post vour code here. this enables us to see where the issue is.

thanks!

Answer 2

a = [[0, 2], [0, 4], [1, 4], [3, 10], [4, 6], [7, 8], [9, 11]]
c = 0
d = len(a)
#print(a[c:d])
#an= a[c:d]
g = []
f = []
n = 1
g.append(a[0])
while c <= len(a)-1:
an = a[c:d]
print("a =", a[c:d])
for start, end in an[1:]:
if start >= an[0][1] and end > an[0][0]:
if [start, end] in g:
pass
else:
g.append([start, end])
#print(start, end)
print()
#n += 1
print("Only one laptop is ok")
else:
if [start, end] in f:
pass
else:
f.append([start, end])
n += 1
print("More than one laptop")
#n += 1

c += 1

print(c)
print("n = ", n)
print("g = ", g)
print("f = ", f)