I tried to turn a regular list into a 2 dimensional list and and add values to those lists but failed,why?

Question

https://code.sololearn.com/cMfH7m4TDRyY/?ref=app

Answer 1

Maybe this does what you want:
a = []
a.append([])
a.append([])
a[0].append(1)
a[1].append(6)
print(a)

Answer 2

https://code.sololearn.com/cbMhHpH415rE/?ref=app

Answer 3

python

Answer 4

No, when a = [6, 5] and you append [2] the output should be [6, 5, [2]]
If you want [[6, 5], [2]] you can use one of these ways:

a = [[6, 5]]
a.append([2])

or

a = []
a.append([6, 5])
a.append([2])

or

a = []
a.append([])
a[0].append(6)
a[0].append(5)
a.append([2])

Answer 5

Line 4:
Not arr[1].append(6), must be arr[0].append(6)

Answer 6

arr = []
arr.append([1])
arr.append([6])
print(*arr)

Answer 7

Lenoname
Think of it as a list of list.
Your list index will now be of form:
a[x][y]
where x is the index relative to a and y is the index relative to a[x]
you just have to use the proper index.

in you example, you have:
a = [6, 5]
and you want to have:
a = [[6, 5],[2]]

you would actually have to create a new list:
a = [a, [2]]👈

🔹because a = [6, 5] is not a = [[6, 5]]

if:
a = [[6, 5]]
then yes,
a.append([2])
would give
a = [[6, 5],[2]]

https://code.sololearn.com/cgFrEb3piq8A/?ref=app

Answer 8

Hi! That’s because you trying to assign a value to a list that dosen’t exist : a[1] does not exist; just a[0].

Answer 9

But didnt i add a dimension with a.append([ ])?

Answer 10

To be shure, try to print(a) to look at it. If you not happy, try something else.

Answer 11

Works fine if i replace [1] with [0], but as far as i know two dimensional lists come in form of: listA=[1,3,4],[3,6,7],[7,5],….
I just want to add another [ ] to the one dimensional list so that it becomes two dimensional and put numbers in it with .append.

Answer 12

In short i wanted: [1],[6] to be printed.

Answer 13

Azamat Shermatov lets say a=[6,5] when i use a.append([2]) the output is [6,5,[2]]
But It should be [[6,5],[2]]