Why there is no parentheses when assigning a function to a function pointer

Question

int (*op[4])(int, int);

op[0] = add;
op[1] = subtract;
op[2] = multiply;
op[3] = divide;
printf("Enter two integers: ");
scanf("%d%d", &x, &y);
printf("Enter 0 to add, 1 to subtract, 2 to multiply, or 3 to divide: ");
scanf("%d", &choice);
result = op[choice](x, y);
printf("\n %d", result);

return 0;
}

int add (int x, int y) {
return(x + y);
}

Answer 1

If you add parenthesis, then its becomes a call to that function, not as assignment according syntaxes..
So with parenthesis, it will call function and store returned value in op[n], Instead of storing function pointer (Hoping on equal compatibility in storage, if not, raise errors..)
so there is no need to add parenthesis in assignment..

Answer 2

Jayakrishna🇮🇳 thanks a lot👊