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Can get this one
Var arr = [1,2,3]; var str = âabcâ; Var x = 1 Do { Arr[x] = str[arr[x]]; <- explain this pls X++; } While (x<arr.length -1); <- and this: it give us 1 loop Alert (arr); Output is 1,c,3
1 Answer
+ 3
arr[1] = str[arr[1]] = str[2] = c
It means second element of the array arr is assigned as c.
while(2<3-1)
Since condition evaluates false, loop stops running and print the updated arr. [1,c,3]