C code

Question

What is the output of this C code?
#include <stdio.h>
main()
{
if (sizeof(int) > -1)
printf("True");
else
printf("False");
}
a) True
b) False

Answer 1

Try it in playground..
What's your doubt here?

edit:
if your doubt is why False as output? then

sizeof(int) returns a long unsigned int type value 4 . In expression evaluation, first the data operand values are all automatically upcasted to higher datatype. so -1 will be upcasted to unsigned long int which is 2^32-1 and it is greater than sizeof(int) (=4 mostly) in any machine.
so it outputs False

edit:

#include<stdio.h>
int main(){

if(sizeof(int) > -1)
printf("True");

else
printf("False");

printf("\n%lu > %lu", sizeof(int),-1); //converted values
return 0;
}

Answer 2

Depends on how C evaluates (int)