Palindrome Numbers challenge help c++

Question

I'm having difficulty with how to reverse the numbers i don't think any of the previous lessons have gone through it, if there's any pointers of lesson or help would be appreciated.

Answer 1

You can also iterate through the number in reverse using a for loop, & decrement each iteration.

Review lesson 16.1 of c++ for details.

Then compare the original num against your new num

Answer 2

Reverse number : n = 234
1) n%10 => returns 4 add to a variable rev
2) n=n/10 makes n = 23

=> rev = 4, n = 23
Repeat these two steps in a loop until n>0
=> rev = 43, n = 2
=> rev = 432 , n = 0

finally, You get rev = 432. Just find how to add..
Finally if original n = 234 is not equal to rev( =432) so it's not polindrome...

Angel Jimenez
I hope you can try now. . . .

Hope it helps..

Answer 3

Here is how I've managed to do it using recursion in c++

https://code.sololearn.com/cWeS0D5HH6Tr/?ref=app