Why giving different value of 1st and 5th even if same pointer and everything same .

Question

https://code.sololearn.com/cWRGsWWtmyJL/?ref=app

Answer 1

Increments applying on pointers, not on it's contents.
Post fix operator has highest precedence than *dereference operator.
so It's evaluated *p++ as *(p++) , and it's a post increment operation so first value is used in print after then increments..

pre fix operator and dereference has same precedence but associativity is right to left.
so *++p is evaluated as *(++p) => *(p=p+1)

Answer 2

Observe that p gets incremented twice by lines 12 and 13. Now p is two positions higher than it started out, so it points to the third element, which holds the value 2.

Answer 3

Yes. Because p is in scope within all of main(), if you change it anywhere in main() (even in a function argument) then the change remains in effect thereafter - until the next change.

Answer 4

Ok thanks

Answer 5

Brian So in pointer specific print also chang value of another coming ?