letter counter

Question

text = input()
text_dict = {}
#your code goes here

text_list = list(text)
text_list2 = list(text)

for i in range(len(text)):
for x in range(len(text)):
y = 0
if text_list[x] == text_list2[x]:
y = y + 1
text_dict[text_list[i]] = y

print(text_dict)

can someone please tell me what’s wrong with this? it’s meant to print the number of letters in a word in dictionary format

Answer 1

What does your if condition do?
It's same as if True:

Answer 2

Oliver clayden ,

just some thoughts from my side:

▪︎we do not need 2 text lists
▪︎we need only one for loop

it could be done this way:

text_list = list(input())
text_dict = {}

#text_list = list(text) # is done with input directly
#text_list2 = list(text) # not required

for char in text_list:
if char in text_dict: # if character already exists: increment number
text_dict[char] += 1
else: # create new element in dict and set value to 1
text_dict[char] = 1

print(text_dict)

Answer 3

text = input()
text_dict = {}
#your code goes here

text_list = list(text)
text_list2 = list(text)

for i in range(len(text)):
y = 0
for x in range(len(text)):
if text_list[i] == text[x]:
y = y + 1
text_dict[text_list[i]] = y

print(text_dict)

Answer 4

just solved it