how to fix loop for Square Numbers?

Question

prints 2 ^ 2 = 9 i know sound's crazy but please check the code 👀

https://code.sololearn.com/c5CzsSp8enpf/?ref=app

Answer 1

thank you John Wells i appreciate your assistance 🙏

Answer 2

n = 2
n3 = 3**2 = n**2 + (n + n + 1) = 2**2 + (2 + 2 +1) = 4 + 5 = 9

Answer 3

thanks john but the real problem at output it prints 3**2 ==16

Answer 4

Because you are using 3 to calculate 3 instead of 2 to calculate 3. Add the n+1 to the print because it belongs there

Answer 5

Everyone of these has n+1 = target square
n = 2
n3 = 3**2 = n**2 + (n + n + 1)
n = 3
n4 = 4**2 = n3 + (n + n + 1)
n = 4
n5 = 5**2 = n4 + (n + n + 1)

Answer 6

n =

***
***
***

=

++o
**+
**+

= (n-1) ^2 ->*
+ 2(n-1) -> +
+1 -> o

But instead of n-1 u used n.