How do i put "if letter appears two times in a list,print deja vu" in python code 😅I'm a beginner

Answer 1

Do not write in the input function

An approach could be to create a set with the input and then compare the length of the set with the length of the original input string.

The output must be written exactly as described in the task description

Answer 2

👉Please tag "Python" when you ask about Python, not "html".

👉Please elaborate what the task is (example input and output)

👉Show your attempt.

Answer 3

Is it a sololearn task?
It asks for input() according to the task description?

Answer 4

You can use the count method of list and conditional statements.

some_list = ['a', 'b', 'c', 'd', 'e', 'a']
letter = input()

if some_list.count(letter) > 1:
print("Deja Vu")
else:
print("Unique")

Answer 5

Input Format:
A string of random letter characters (no numbers or other buttons were pressed).

Output Format:
A string that says 'Deja Vu' if any letter is repeated in the input string, or a string that says 'Unique' if there are no repeats

Answer 6

letters="aa,bb,cc,df,ee,ff,g,hh,ii,jj,kk,ll,mm,nn,oo,pp,qq,rr,ss,tt,uu,vv,ww,xx,yy,zz"
string="hello"
if letters in string:
print("Deja vu")
elif letters not in string:
print("Unique

Here is my attempt above

Answer 7

Yes,it does,but i did it like that to see if it will work with my input string of which it doesn't

Answer 8

letters=['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z/n']
string=(input("string"))
pos=0
long=len(letters)
if letters[pos]in string*2:
print("deja vu")
else:
print("unique")

This here was my second attempt

Answer 9

Sandeep i tried this but,it works with some words but some,no

Answer 10

Lisa may you please elaborate more on your answer please

Answer 11

M.e.r.c.y📍🖤 it should work with everything. Maybe try adding an elif condition.

-----
You can use the count method of list and conditional statements.

some_list = ['a', 'b', 'c', 'd', 'e', 'a']
letter = input()

if some_list.count(letter) > 1:
print("Deja Vu")
elif some_list.count(letter) == 1:
print("Unique")
else:
print("")
----

Answer 12

if string.count() == 2:
# code here

I dont know, this might help though.