0

Does anybody know why the dictionary values are all the last element of the second list?

Here's the code: l1=[1,2,3,4,5,6,7] l2=[1,4,9,16,25,36,49] dict2={} for i in l1:     for j in l2:       dict2[i]=j print(dict2.items()) I think there's a problem with the second for loop but i can't really point out what's going wrong here. If anyone could help please let me know.

28th Apr 2022, 1:11 AM
Syrine Ayedi
Syrine Ayedi - avatar
5 Answers
+ 2
Yeah the second for loop keeps reassigning all the values from l2 to the same key in dict2 until it finally assigns it the last one The second for loop is basically the equivalent of: dict2[i]=j Ahsen haja taaml for loop wahda kima 9al raul walla more advanced approach kn testaalmha behya zeda is : for i , j in zip(l1,l2): dict2[i]=j this way tloopi en parallĂšle bin l1 w l2
28th Apr 2022, 5:43 AM
FeDi BbM
FeDi BbM - avatar
+ 1
This is saying for each item in l1 Keep on assigning each item in l2 So it goes dict[1] = 1 dict[1] = 4 dict[1] = 9 
. Until dict[1] = 49 Then same thing for every element in l1 i think what you want is simply one for loop for i in range( len(l1) ): dict[ l1[i] ] = l2[i]
28th Apr 2022, 2:09 AM
Raul Ramirez
Raul Ramirez - avatar
+ 1
FeDi BbM thank you so much for your response it really helped 😊
30th Apr 2022, 9:27 PM
Syrine Ayedi
Syrine Ayedi - avatar
+ 1
Syrine Ayedi anytime
30th Apr 2022, 10:27 PM
FeDi BbM
FeDi BbM - avatar
0
Raul Ramirez thank you so much for your response it really helped 😊
30th Apr 2022, 9:28 PM
Syrine Ayedi
Syrine Ayedi - avatar